function validEmail(emailStr)
{
//	code downloaded from javascript.internet.com

	/* The following variable tells the rest of the function whether or not
	to verify that the address ends in a two-letter country or well-known
	TLD.  1 means check it, 0 means don't. */
	var checkTLD = 1;

	/* The following is the list of known TLDs that an e-mail address must end with. */
	var knownDomsPat = /^(com|net|org|edu|int|mil|gov|arpa|biz|aero|name|coop|info|pro|museum)$/;

	/* The following pattern is used to check if the entered e-mail address
	fits the user@domain format.  It also is used to separate the username
	from the domain. */
	var emailPat = /^(.+)@(.+)$/;

	/* The following string represents the pattern for matching all special
	characters.  We don't want to allow special characters in the address. 
	These characters include ( ) < > @ , ; : \ " . [ ] */
	var specialChars = '\\(\\)><@,;:\\\\\\\"\\.\\[\\]';

	/* The following string represents the range of characters allowed in a 
	username or domainname.  It really states which chars aren't allowed.*/
	var validChars = '\[^\\s' + specialChars + '\]';

	/* The following pattern applies if the "user" is a quoted string (in
	which case, there are no rules about which characters are allowed
	and which aren't; anything goes).  E.g. "jiminy cricket"@disney.com
	is a legal e-mail address. */
	var quotedUser = '(\"[^\"]*\")';

	/* The following pattern applies for domains that are IP addresses,
	rather than symbolic names.  E.g. joe@[123.124.233.4] is a legal
	e-mail address. NOTE: The square brackets are required. */
	var ipDomainPat = /^\[(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})\]$/;

	/* The following string represents an atom (basically a series of non-special characters.) */
	var atom = validChars + '+';

	/* The following string represents one word in the typical username.
	For example, in john.doe@somewhere.com, john and doe are words.
	Basically, a word is either an atom or quoted string. */
	var word = '(' + atom + '|' + quotedUser + ')';

	// The following pattern describes the structure of the user
	var userPat = new RegExp('^' + word + '(\\.' + word + ')*$');

	/* The following pattern describes the structure of a normal symbolic
	domain, as opposed to ipDomainPat, shown above. */
	var domainPat = new RegExp('^' + atom + '(\\.' + atom + ')*$');

	emailStr = emailStr.toLowerCase();

	/* Begin with the coarse pattern to simply break up user@domain into
	different pieces that are easy to analyze. */
	var matchArray = emailStr.match(emailPat);
	if (matchArray == null)
	{
		/* Too many/few @'s or something; basically, this address doesn't
		even fit the general mould of a valid e-mail address. */

//		alert('Email address seems incorrect (check @ and .)');
		return false;
	}

	var user = matchArray[1];
	var domain = matchArray[2];

	// Start by checking that only basic ASCII characters are in the strings (0-127).
	for (i = 0; i < user.length; i++)
	{
		if (user.charCodeAt(i) > 127)
		{
//			alert('This username contains invalid characters.');
			return false;
	   }
	}
	for (i = 0; i < domain.length; i++)
	{
		if (domain.charCodeAt(i) > 127)
		{
//			alert('This domain name contains invalid characters.');
			return false;
		}
	}

	// See if "user" is valid 
	if (user.match(userPat) == null)
	{
		// user is not valid
//		alert('The username doesn\'t seem to be valid.');
		return false;
	}

	/* if the e-mail address is at an IP address (as opposed to a symbolic
	host name) make sure the IP address is valid. */
	var IPArray = domain.match(ipDomainPat);
	if (IPArray != null)
	{
		// this is an IP address
		for (var i = 1; i <= 4; i++)
		{
			if (IPArray[i] > 255)
			{
//				alert('Destination IP address is invalid!');
				return false;
			}
		}
		return true;
	}

	// Domain is symbolic name.  Check if it's valid.
	var atomPat = new RegExp('^' + atom + '$');
	var domArr = domain.split('.');
	var len = domArr.length;
	for (i = 0; i < len; i++)
	{
		if (domArr[i].search(atomPat) == -1)
		{
//			alert('The domain name does not seem to be valid.');
			return false;
	   }
	}

	/* domain name seems valid, but now make sure that it ends in a
	known top-level domain (like com, edu, gov) or a two-letter word,
	representing country (uk, nl), and that there's a hostname preceding 
	the domain or country. */
	if (checkTLD && domArr[domArr.length - 1].length != 2 && domArr[domArr.length - 1].search(knownDomsPat) == -1)
	{
//		alert('The address must end in a well-known domain or two letter country.');
		return false;
	}

	// Make sure there's a host name preceding the domain.
	if (len < 2)
	{
//		alert('This address is missing a hostname!');
		return false;
	}

	// If we've gotten this far, everything's valid!
	return true;
}

function validCollegeEmail(emailStr)
{
//	code downloaded from javascript.internet.com

	/* The following variable tells the rest of the function whether or not
	to verify that the address ends in a two-letter country or well-known
	TLD.  1 means check it, 0 means don't. */
	var checkTLD = 1;

	/* The following is the list of known TLDs that an e-mail address must end with. */
	var knownDomsPat = /^(edu|gov|mil|us)$/;

	/* The following pattern is used to check if the entered e-mail address
	fits the user@domain format.  It also is used to separate the username
	from the domain. */
	var emailPat = /^(.+)@(.+)$/;

	/* The following string represents the pattern for matching all special
	characters.  We don't want to allow special characters in the address. 
	These characters include ( ) < > @ , ; : \ " . [ ] */
	var specialChars = '\\(\\)><@,;:\\\\\\\"\\.\\[\\]';

	/* The following string represents the range of characters allowed in a 
	username or domainname.  It really states which chars aren't allowed.*/
	var validChars = '\[^\\s' + specialChars + '\]';

	/* The following pattern applies if the "user" is a quoted string (in
	which case, there are no rules about which characters are allowed
	and which aren't; anything goes).  E.g. "jiminy cricket"@disney.com
	is a legal e-mail address. */
	var quotedUser = '(\"[^\"]*\")';

	/* The following string represents an atom (basically a series of non-special characters.) */
	var atom = validChars + '+';

	/* The following string represents one word in the typical username.
	For example, in john.doe@somewhere.com, john and doe are words.
	Basically, a word is either an atom or quoted string. */
	var word = '(' + atom + '|' + quotedUser + ')';

	// The following pattern describes the structure of the user
	var userPat = new RegExp('^' + word + '(\\.' + word + ')*$');

	/* The following pattern describes the structure of a normal symbolic
	domain, as opposed to ipDomainPat, shown above. */
	var domainPat = new RegExp('^' + atom + '(\\.' + atom + ')*$');

	/* Begin with the coarse pattern to simply break up user@domain into
	different pieces that are easy to analyze. */
	var matchArray = emailStr.match(emailPat);
	if (matchArray == null)
	{
		/* Too many/few @'s or something; basically, this address doesn't
		even fit the general mould of a valid e-mail address. */

//		alert('Email address seems incorrect (check @ and .)');
		return false;
	}

	var user = matchArray[1];
	var domain = matchArray[2];

	// Start by checking that only basic ASCII characters are in the strings (0-127).
	for (i = 0; i < user.length; i++)
	{
		if (user.charCodeAt(i) > 127)
		{
//			alert('This username contains invalid characters.');
			return false;
	   }
	}
	for (i = 0; i < domain.length; i++)
	{
		if (domain.charCodeAt(i) > 127)
		{
//			alert('This domain name contains invalid characters.');
			return false;
		}
	}

	// See if "user" is valid 
	if (user.match(userPat) == null)
	{
		// user is not valid
//		alert('The username doesn\'t seem to be valid.');
		return false;
	}

	// Domain is symbolic name.  Check if it's valid.
	var atomPat = new RegExp('^' + atom + '$');
	var domArr = domain.split('.');
	var len = domArr.length;
	for (i = 0; i < len; i++)
	{
		if (domArr[i].search(atomPat) == -1)
		{
//			alert('The domain name does not seem to be valid.');
			return false;
	   }
	}

	/* domain name seems valid, but now make sure that it ends in a
	known top-level domain (like com, edu, gov), and that there's a hostname preceding 
	the domain or country. */
	if (checkTLD && domArr[domArr.length - 1].search(knownDomsPat) == -1)
	{
//		alert('The address must end in a well-known domain or two letter country.');
		return false;
	}

	// Make sure there's a host name preceding the domain.
	if (len < 2)
	{
//		alert('This address is missing a hostname!');
		return false;
	}

	/* if the top-level domain is .us, make sure it's a state.xxxx.us, co[unty].xxx.xxx.us,
	ci[ty].xxx.xxx.us address, or lib.xxxx.us */
	if (domArr[domArr.length - 1].toLowerCase() == 'us')
	{
		if (len > 2 && (domArr[domArr.length - 3].toLowerCase() == 'state' || domArr[domArr.length - 3].toLowerCase() == 'k12' || domArr[domArr.length - 3].toLowerCase() == 'lib'))
		{
			return true;
		}
		else if (len > 3 && (domArr[domArr.length - 4].toLowerCase() == 'co' || domArr[domArr.length - 4].toLowerCase() == 'ci' || domArr[domArr.length - 4].toLowerCase() == 'county' || domArr[domArr.length - 4].toLowerCase() == 'city'))
		{
			return true;
		}
		else
		{
			return false;
		}
	}

	// If we've gotten this far, everything's valid!
	return true;
}